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date_add> <Fonctions Date/Heure
[edit] Last updated: Fri, 17 May 2013

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checkdate

(PHP 4, PHP 5)

checkdateValide une date grégorienne

Description

bool checkdate ( int $month , int $day , int $year )

Vérifie la validité d'une date formée par les arguments. Une date est considérée comme valide si chaque paramètre est défini correctement.

Liste de paramètres

month

Le mois doit être compris entre 1 et 12.

day

Le jour doit être un jour autorisé par le mois donné. Les années bissextiles sont prises en compte.

year

L'année est comprise entre 1 et 32767 inclus.

Valeurs de retour

Retourne TRUE si la date fournie est valide, FALSE sinon.

Exemples

Exemple #1 Exemple avec checkdate()

<?php
var_dump
(checkdate(12312000));
var_dump(checkdate(2292001));
?>

L'exemple ci-dessus va afficher :

bool(true)
bool(false)

Voir aussi

  • mktime() - Retourne le timestamp UNIX d'une date
  • strtotime() - Transforme un texte anglais en timestamp



date_add> <Fonctions Date/Heure
[edit] Last updated: Fri, 17 May 2013
 
add a note add a note User Contributed Notes checkdate - [22 notes]
up
3
bharath.kishore.a AT gmail. DOT com
1 year ago
Here is another crooked way to check if given data is valid DATETIME or not.

function checkDateTime($data) {
    if (date('Y-m-d H:i:s', strtotime($data)) == $data) {
        return true;
    } else {
        return false;
    }
}
up
1
sebagr@gmail
4 years ago
Here's a nice snippet to check if user input is valid:

<?php

$date_format
= 'Y-m-d';
$input = '2009-03-03';

$input = trim($input);
$time = strtotime($input);

$is_valid = date($date_format, $time) == $input;

print
"Valid? ".($is_valid ? 'yes' : 'no');

?>
up
0
mohammed dot aas2012 at gmail dot com
6 months ago
format should be in array like: array("m","d","y")

<?php
function isValidDate($strDate,$format,$ex) {
     
$valid = false;
      if(
is_array($format) && count($format) == 3 && count(explode($ex,$strDate))==3)
      {
        
$date = array_combine($format,explode($ex,$strDate));
         if(
intval($date['m']) && intval($date['d']) && intval($date['y'])){
           
$m = $date['m']; $d = $date['d']; $y = $date['y'];
           
$valid = checkdate($m,$d,$y);
         }
      }
      return
$valid;
   }
?>
up
0
el dot vartauy__ at t__gmail dot com
5 years ago
for funny leap year detection:
<?php
function is_leap($year=NULL) {
    return
checkdate(2, 29, ($year==NULL)? date('Y'):$year); // true if is a leap year
}
?>
up
0
wasile_ro[at]yahoo[dot]com
5 years ago
here's a cool function to validate a mysql datetime:

<?php
function isValidDateTime($dateTime)
{
    if (
preg_match("/^(\d{4})-(\d{2})-(\d{2}) ([01][0-9]|2[0-3]):([0-5][0-9]):([0-5][0-9])$/", $dateTime, $matches)) {
        if (
checkdate($matches[2], $matches[3], $matches[1])) {
            return
true;
        }
    }

    return
false;
}
?>
up
0
a34 at yahoo dot com
5 years ago
checkData function posted below does not consider a date entered such as 03/27c/2000.   The c will cause it to crash.  Here is the fix.

<?php
function checkData($mydate) {
      
    list(
$yy,$mm,$dd)=explode("-",$mydate);
    if (
is_numeric($yy) && is_numeric($mm) && is_numeric($dd))
    {
        return
checkdate($mm,$dd,$yy);
    }
    return
false;           
}
?>
up
-1
rfeugenio at gmail dot com
4 years ago
<?php

// This is a simple function that will get the last day of the month.

function GetLastDayofMonth($year, $month) {
    for (
$day=31; $day>=28; $day--) {
        if (
checkdate($month, $day, $year)) {
            return
$day;
        }
    }   
}

?>
up
-1
nisspaATgmail
3 months ago
Function to increment date by one day...
<?php

function DateIncrement (&$year,  &$month, &$day)
{
      if(!
checkdate($month, $day, $year)){
            if (!
checkdate ($month, $day +1, $year)
            {
                if (!
checkdate($month + 1, 1, $year)
        {
                   
$month = 1;
                   
$year = $year +1;
                   
$day =1;
                          return
false;
                }else
        {
                   
$month = $month +1;
                   
$day = 1;
                          return
false;
                }
             } else {
               
$day = $day + 1;
                        return
false;
             }
        }else{
            return
true;
        }
}       

?>
up
-1
ystein M
4 years ago
I think there is an error in the function from bmauser below. $regexp is overwritten. Here's another version which also accepts missing zeros and two digits year notation.

This function checks date if matches given format and validity of the date.

<?php
/**
 * Checks date if matches given format and validity of the date.
 * Examples:
 * <code>
 * is_date('22.22.2222', 'mm.dd.yyyy'); // returns false
 * is_date('11/30/2008', 'mm/dd/yyyy'); // returns true
 * is_date('30-01-2008', 'dd-mm-yyyy'); // returns true
 * is_date('2008 01 30', 'yyyy mm dd'); // returns true
 * </code>
 * @param string $value the variable being evaluated.
 * @param string $format Format of the date. Any combination of <i>mm<i>, <i>dd<i>, <i>yyyy<i>
 * with single character separator between.
 */
function is_valid_date($value, $format = 'dd.mm.yyyy'){
    if(
strlen($value) >= 6 && strlen($format) == 10){
       
       
// find separator. Remove all other characters from $format
       
$separator_only = str_replace(array('m','d','y'),'', $format);
       
$separator = $separator_only[0]; // separator is first character
       
       
if($separator && strlen($separator_only) == 2){
           
// make regex
           
$regexp = str_replace('mm', '(0?[1-9]|1[0-2])', $format);
           
$regexp = str_replace('dd', '(0?[1-9]|[1-2][0-9]|3[0-1])', $regexp);
           
$regexp = str_replace('yyyy', '(19|20)?[0-9][0-9]', $regexp);
           
$regexp = str_replace($separator, "\\" . $separator, $regexp);
            if(
$regexp != $value && preg_match('/'.$regexp.'\z/', $value)){

               
// check date
               
$arr=explode($separator,$value);
               
$day=$arr[0];
               
$month=$arr[1];
               
$year=$arr[2];
                if(@
checkdate($month, $day, $year))
                    return
true;
            }
        }
    }
    return
false;
}
?>

[NOTE BY danbrown AT php DOT net: Original function was written by (bmauser AT gmail) on 16-DEC-2008.]
up
-1
manuel84**at**mp4**dot**it
6 years ago
If you have a date like this gg/mm/aaaa and you'd like to verify that it is in the Italian Format you can use a function like this.
For other date format you can take this code and simply modify the list and explode line
<?php
/**
* check a date in the Italian format
*/
function checkData($date)
{
    if (!isset(
$date) || $date=="")
    {
        return
false;
    }
   
    list(
$dd,$mm,$yy)=explode("/",$date);
    if (
$dd!="" && $mm!="" && $yy!="")
    {
        return
checkdate($mm,$dd,$yy);
    }
   
    return
false;
}
?>
up
-1
saturn at ax dot com dot tw
4 years ago
I wrote a simple function to converter datetime to UNIX timestamp. If the input time with error format, the function will return current timestamp.

<?php
function datetime2timestamp($datetime)
{
   
$datetime = str_replace('-', ' ', $datetime);
   
$datetime = str_replace('/', ' ', $datetime);
   
$datetime = str_replace(':', ' ', $datetime);
   
$array = explode(' ', $datetime);

   
$year   = $array[0];
   
$month  = $array[1];
   
$day    = $array[2];
   
$array[3] ? $hour   = $array[3] : $hour   = '00';
   
$array[4] ? $minute = $array[4] : $minute = '00';
   
$array[5] ? $second = $array[5] : $second = '00';
   
    if (
preg_match("/^(\d{4}) (\d{2}) (\d{2}) ([01][0-9]|2[0-3]) ([0-5][0-9]) ([0-5][0-9])$/", "$year $month $day $hour $minute $second", $matches)) {
        if (
checkdate($matches[2], $matches[3], $matches[1])) {
        return
mktime(intval($hour), intval($minute), intval($second), intval($month), intval($day), intval($year));
        } else {
        return
time();
        }       
    } else {
    return
time();
    }
}
?>
up
-2
James Luckhurst
4 years ago
<?php
/*
## converts a given date format to another date format returns date if the checked date given is valid; otherwise returns NULL
## $s_date the date in e.g. dd/mm/yyyy
## $s_from, $s_to date formats from to i.e. convertdate('13/04/2009','eng','iso','-'); output: 2009-04-13
## date formats available
## 'eng' = dd/mm/yyyy
## 'usa' = mm/dd/yyyy
## 'iso' = yyyy/mm/dd
## $s_return_delimiter returned delimiter e.g. '-' would return dd-mm-yyyy
*/
function convertdate($s_date,$s_from,$s_to,$s_return_delimiter) {

   
$s_return_date = '';
   
$s_from = strtolower($s_from);
   
$s_to = strtolower($s_to);
   
$s_date = str_replace(array('\'', '-', '.', ',', ' '), '/', $s_date);
   
$a_date = explode('/', $s_date);
   
    switch(
$s_from) {
        case
'eng': # dd/mm/yyyy
           
$day = $a_date[0];
           
$month = $a_date[1];
           
$year = $a_date[2];
        break;
        case
'usa'# mm/dd/yyyy
           
$month = $a_date[0];
           
$day = $a_date[1];
           
$year = $a_date[2];
        break;
        case
'iso': # yyyy/mm/dd
           
$year = $a_date[0];
           
$month = $a_date[1];
           
$day = $a_date[2];
        break;
        default:
# error message
           
user_error('function convertdate(string $s_date, string $s_from, string $s_to, string $s_return_delimiter) $s_from not a valid type of \'eng\', \'usa\' or \'iso\'');
            return
NULL;
    }

   
# substitution fixes of valid alternative human input e.g. 1/12/08
   
if (strlen($day)==1) { $day='0'.$day; } # day -trailing zero missing
   
if (strlen($month)==1) { $month='0'.$month; } # month -trailing zero missing
   
if (strlen($year)==3) { $year=substr(date('Y'),0,strlen(date('Y'))-3).$year; } # year -millennium missing
   
if (strlen($year)==2) { $year=substr(date('Y'),0,strlen(date('Y'))-2).$year; } # year -century missing
   
if (strlen($year)==1) { $year=substr(date('Y'),0,strlen(date('Y'))-1).$year; } # year -decade missing

   
switch($s_to) {
        case
'eng': # dd/mm/yyyy
           
$s_return_date = $day.$s_return_delimiter.$month.$s_return_delimiter.$year;
        break;
        case
'usa'# mm/dd/yyyy
           
$s_return_date = $month.$s_return_delimiter.$day.$s_return_delimiter.$year;
        break;
        case
"iso": # yyyy/mm/dd
           
$s_return_date = $year.$s_return_delimiter.$month.$s_return_delimiter.$day;
        break;
        default:
# error message
           
user_error('function convertdate(string $s_date, string $s_from, string $s_to, string $s_return_delimiter) $s_to not a valid type of \'eng\', \'usa\' or \'iso\'');
            return
NULL;
    }

   
# if it's an invalid calendar date e.g. 40/02/2009 or rt/we/garbage
   
if (!is_numeric($month) || !is_numeric($day) || !is_numeric($year)) {
        return
NULL;
    } elseif (!
checkdate($month, $day, $year)) {
        return
NULL;
    }

    return
$s_return_date;
}

echo
convertdate('13/04/2009','eng','iso','-');
?>
up
-2
iamcanadian1973 at gmail dot com
4 years ago
[NOTE BY danbrown AT php DOT net: The author's purpose for this function is to determine whether or not a given string $str is a date using a static algorithm.]

<?php
function is_date( $str )
{
 
$stamp = strtotime( $str );
 
  if (!
is_numeric($stamp))
  {
     return
FALSE;
  }
 
$month = date( 'm', $stamp );
 
$day   = date( 'd', $stamp );
 
$year  = date( 'Y', $stamp );
 
  if (
checkdate($month, $day, $year))
  {
     return
TRUE;
  }
 
  return
FALSE;
}
?>
up
-2
venadder at yahoo dot ca
4 years ago
Here is a simple IsDate function, using purely PHP functions( A Check for $Stamp can be added to see if it's a legal Unix timestamp ):

<?php
function IsDate( $Str )
{
 
$Stamp = strtotime( $Str );
 
$Month = date( 'm', $Stamp );
 
$Day   = date( 'd', $Stamp );
 
$Year  = date( 'Y', $Stamp );

  return
checkdate( $Month, $Day, $Year );
}
?>
up
-2
parris dot varney at gmail dot com
4 years ago
I put together an is_date function using checkdate.  Works the same as is_numeric.

<?php
   
public static function is_date($date)
    {
       
$date = str_replace(array('\'', '-', '.', ','), '/', $date);
       
$date = explode('/', $date);

        if(   
count($date) == 1 // No tokens
           
and    is_numeric($date[0])
            and   
$date[0] < 20991231 and
            (   
checkdate(substr($date[0], 4, 2)
                        ,
substr($date[0], 6, 2)
                        ,
substr($date[0], 0, 4)))
        )
        {
            return
true;
        }
       
        if(   
count($date) == 3
           
and    is_numeric($date[0])
            and   
is_numeric($date[1])
            and
is_numeric($date[2]) and
            (   
checkdate($date[0], $date[1], $date[2]) //mmddyyyy
           
or    checkdate($date[1], $date[0], $date[2]) //ddmmyyyy
           
or    checkdate($date[1], $date[2], $date[0])) //yyyymmdd
       
)
        {
            return
true;
        }
       
        return
false;
    }
?>
up
-2
doob_ at gmx dot de
4 years ago
<?php

/*
** check a date
** dd.mm.yyyy || mm/dd/yyyy || dd-mm-yyyy || yyyy-mm-dd
*/

function check_date($date) {
    if(
strlen($date) == 10) {
       
$pattern = '/\.|\/|-/i';    // . or / or -
       
preg_match($pattern, $date, $char);
       
       
$array = preg_split($pattern, $date, -1, PREG_SPLIT_NO_EMPTY);
       
        if(
strlen($array[2]) == 4) {
           
// dd.mm.yyyy || dd-mm-yyyy
           
if($char[0] == "."|| $char[0] == "-") {
               
$month = $array[1];
               
$day = $array[0];
               
$year = $array[2];
            }
           
// mm/dd/yyyy    # Common U.S. writing
           
if($char[0] == "/") {
               
$month = $array[0];
               
$day = $array[1];
               
$year = $array[2];
            }
        }
       
// yyyy-mm-dd    # iso 8601
       
if(strlen($array[0]) == 4 && $char[0] == "-") {
           
$month = $array[1];
           
$day = $array[2];
           
$year = $array[0];
        }
        if(
checkdate($month, $day, $year)) {    //Validate Gregorian date
           
return TRUE;
       
        } else {
            return
FALSE;
        }
    }else {
        return
FALSE;    // more or less 10 chars
   
}
}

check_date('21.02.1983');
check_date('21-02-1983');
check_date('02/21/1983'); // Common U.S. writing
check_date('1983-02-21'); // iso 8601

?>
up
-2
jens wittmann
5 years ago
for checking the rime use this:

<?php
function checktime($hour, $minute) {
    if (
$hour > -1 && $hour < 24 && $minute > -1 && $minute < 60) {
        return
true;
    }
}
?>
up
-2
brenig code
5 years ago
<?php

/**
* check a date combo of the 2
*/
function checkData($date)
{
    if (!isset(
$date) || $date=="")
    {
        return
false;
    }
  
    list(
$dd,$mm,$yy)=explode("/",$date);
    if (
$dd!="" && $mm!="" && $yy!="")
    {
    if (
is_numeric($yy) && is_numeric($mm) && is_numeric($dd))
        {
            return
checkdate($mm,$dd,$yy);

        }
    }  
    return
false;

}
?>
up
-3
Martin Kuchar
8 months ago
It may be also used with strings and also with leading zero:

checkdate("03","08","2012") is TRUE
up
-3
pradeepkumarprajapati3 at yahoo dot co dot in
1 year ago
don't use strtotime() to format inputs to checkdate(). It would give false results.
Eg,
Below function would return true though it should have been false

<?php
$str
= '2011-11-31'; //invalid date, november has 30 days only
function isDateValid($str)
{
 
$stamp = strtotime($str);
  if (!
is_numeric($stamp))
     return
FALSE;
 
 
//checkdate(month, day, year)
 
if ( checkdate(date('m', $stamp), date('d', $stamp), date('Y', $stamp)) )
  {
     return
TRUE;
  }
  return
FALSE;
}
?>

The reason is that strtotime() coverts 2011-11-31 to 2011-12-01.
check with date('Y-m-d', strtotime('2011-11-31'))
up
-3
Anonymous
3 years ago
Beware that checkdate can not be used as validation to check if a date is correct.

The example below will return bool(true) which can result that the <script> part is inserted into the database.

<?php

$date
= "01-01-1980 <script>alert('test');</script>";
$aDate_parts = preg_split("/[\s-]+/", $date);

var_dump(
   
checkdate(
       
$aDate_parts[1], // Month
       
$aDate_parts[0], // Day
       
$aDate_parts[2] // Year
   
)
);

?>
up
-4
Anonymous
1 year ago
This is a very good function to check if a date format is valid (with regex).

For example:

2012-2-28 = Valid
2012-2-29 = Valid (leap year)
2012-2-30 = Invalid

2012-1-30 = Valid
2012-1-31 = Valid
2012-2-32 = Invalid

Ensure there are no spaces in the preg_match function:

<?php
 
function Valid_Date_Format($date)
  {
   
$converted=str_replace('/','-',$date);

    if(
preg_match("/^((((19|20)(([02468][048])|([13579][26]))-02-29))|((20[0-9][0-9])|(19[0-9][0-9]))-((((0[1-9])|
(1[0-2]))-((0[1-9])|(1\d)|(2[0-8])))|((((0[13578])|(1[02]))-31)|(((0[1,3-9])|
(1[0-2]))-(29|30)))))$/"
,$converted)===1)
    {
      return
TRUE;
    }

    return
FALSE;
  }
?>

I don't know where I got the original code from but I've not found anything better.

 
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