(PHP 5)

ibase_gen_idافزودن تولیدکننده نامدار و بازگرداندن مقدار جدید


mixed ibase_gen_id ( string $generator [, int $increment = 1 [, resource $link_identifier = NULL ]] )

This function is currently not documented; only its argument list is available.

Return Values

بازگرداندن تولیدکننده مقدار جدید به عنوان عدد صحیح یا به عنوان رشته اگر مقدار بسیار بزرگ باشد.

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User Contributed Notes 3 notes

7 years ago
You need to know the generator´s value after INSERT:

Before INSERT-Statement run

$nextnumber=ibase_gen_id ("GEN_NAME",1);

GEN_NAME: is the generator´s name

1: means add 1 to actual value of generator

$nextnumber: is variable to store generators value after incrementing

In the INSERT-Statement you can use $nextnumber instead of using generator directly like in:
INSERT INTO test (field1, field2) VALUES gen_id(gen_test_id, 1), 'testme');
escoric at latinmail dot com
9 years ago
$sql="INSERT INTO mitabla(campo1,campo2,..campo n) VALUES(GEN_ID(mitabla1_codigo_gen,1),'contenido 1', 'contenido 2', 'contenido n' )";
mfischer at php dot net
9 years ago
Question arose on php-dev:

How does ibase_gen_id() handle 64bit values?

Interbase 6/Firebird generators are always 64-bit signed integers
(Firebird's BIGINT type), regardless of the platform the client is
On 64-bit platforms, this will never require conversion as PHP's int
type is 64 bits wide on those platforms. On 32-bit platforms, the
generated value is converted to a string if it exceeds the limits of a
32-bit signed integer.
(This behaviour is consistent with the ibase_fetch_*() functions, that
will use strings to represent numerical values that cannot be represented
accurately using native PHP numerical types.)

[Edited by PHP/Interbase maintainer.]
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